Reading the Numbers on a Sefcu Check

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C++ Plan to Check Whether Number is Even or Odd

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A number is even if it is divisible past two and odd if it is non divisible by two.

Some of the even numbers are −

2, four, 6, 8, 10, 12, 14, xvi

Some of the odd numbers are −

1, iii, 5, 7, 9, 11, thirteen, 15, 17

Bank check Whether Number is Even or Odd using Modulus

A program to check whether number is fifty-fifty or odd using modulus is as follows.

Example

 Live Demo

#include <iostream> using namespace std; int main() {    int num = 25;    if(num % 2 == 0)    cout<<num<<" is even";    else    cout<<num<<" is odd";    return 0; }

Output

25 is odd

In the to a higher place program, the number num is divided by 2 and its remainder is observed. If the remainder is 0, then the number is fifty-fifty. If the remainder is 1, then the number is odd.

if(num % two == 0)    cout<<num<<" is fifty-fifty"; else    cout<<num<<" is odd";

Check Whether Number is Even or Odd Using Bitwise AND

A number is odd if it has 1 equally its rightmost bit in bitwise representation. It is even if it has 0 every bit its rightmost scrap in bitwise representation. This tin be establish by using bitwise AND on the number and ane. If the output obtained is 0, and so the number is even and if the output obtained is 1, then the number is odd.

A plan to check whether number is even or odd using Bitwise AND is as follows −

Example

 Live Demo

#include <iostream> using namespace std; int main() {    int num = 7;    if((num & i) == 0)    cout<<num<<" is fifty-fifty";    else    cout<<num<<" is odd";    render 0; }

Output

7 is odd

In the in a higher place program, bitwise AND is done on num and one. If the output is 0, and so num is even, otherwise num is odd.

if((num & one) == 0) cout<<num<<" is fifty-fifty"; else cout<<num<<" is odd";

Published on 26-Sep-2018 13:46:30

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Reading the Numbers on a Sefcu Check

Source: https://www.tutorialspoint.com/cplusplus-program-to-check-whether-number-is-even-or-odd

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